Question

The correct order regarding the electronegativity of hybrid
orbitals of carbon is
(a) sp > sp² > sp³ (b) sp < sp² > sp³
(c) sp < sp² < sp³ (d) sp > sp² < sp³

Answer 1

The correct order regarding the electronegativity of hybrid  orbitals of carbon is (a) sp > sp² > sp³.

Explanation:

The orbitals with more s characters are more electronegative. The s character in case of sp, sp² and sp³ are given below,

sp = 50%

sp² = 33%

sp³ = 25%

So the correct order of electronegativity of hybrid  orbitals of carbon is (a) sp > sp² > sp³.