The correct pair of position isomers is/are:
(A)
H₂C
H₂C
H
H
(B)
&
OCH,
0-CH,
H₂C-
(C) H3C-
-CH₃
OH
НО
(D) H3C
*****
& HC
CH3
=CH₂
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The given image is Self-Explanatory.
We know that following are the cases when a compound is Optically Inactive:
1. When it does not have a chiral Carbon Atom eg.: Methyl bromide
2. When it has a Plane or Axis of Symmetry eg.: Tartaric Acid (these compounds are called as Meso Compounds)
3. When it forms a Racemic Mixture eg.: Equimolar mixture of d-Lactic Acid and l-Lactic Acid.
The given compound in the question possesses an Axis of Symmetry (shown in the attached image). Hence, it is Optically Inactive.
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