the correct set of four quantum numbers for the valance electon of sodium atom is (z=11)
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The correct set of four quantum numbers for the outermost electron of sodium (Z=11) is 3,0,0, 1/2
The electronic configuration of Na is 1s
2/ 2s
2/2p
6/ 3s × 1
Thus, the last electron is in 3s sub-shell.
For 3s sub-shell, n=3,
l=0, m=0 and s=± 1/2
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Answer:
n=3, l=0(s),m=0, s=+-1/2
Explanation:
last electron is in 3rd shell. So n=3.
Only one electron present, hence l=0(s subshell).
Since l=0, therefore m=0.
Spin quantum no.-(s) can take any value, +1/2 or-1/2.
Hope I hv cleared your doubt.
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