Question

the correct set of four Quantum numbers for the valence electrons caesium

Answer 1

Caesium is element number 55.
Its electric configuration is [Xe]6s1.
So, the principal quantum number, which describes the shell, is n=6,as it is in the 6th shell.
The azimuthal quantum number, which the describes the sub shell, is l=0, as it is in the s- sub-shell. Remember that l={l|lEW;l<n}.
The magnetic quantum number, which describes the orbital, is m=0,as it is the only orbital present in the s-sub-shell. Remember that m={m|mEZ;-l<m<l}.
The spin quantum number, which describes the spin of the electrons, s={1/2,-1/2}. Remember that there is only one electron in the orbital in the question. So, it's spin maybe any of the two values. (If there were two, electron under consideration may have spin (+1/2),but the other electron necessarily has the opposite spin).

Answer 2

$\huge\pink{Hi}$

$\huge\boxed{Answer:-}$

Quantum numbers of caesium

Atomic number of caesium is 55

last electron is in sixth shell and S orbital....soo...

principal quantum number ( n ) = 6

azimuthal quantum number ( l ) = 0

magnetic quantum number ( m ) = 0

spin quantum number ( s ) = +1/2

❤️Hope it helps you ❤️

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