the correct set of quantum number for the last electron in na+ ion is
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Answer:
The quantum number for Sodium is this: 1s2 => n = 1 l= 0 m=0
s = +/- 1/2
2s2 => n=2 l=0 m= 0 s = +/- 1/2
2p6 => n = 2 ; l = 1 , m = -1 , 0 , +1 s = +/- 1/2
3s1 => n = 3 l=0 m=0 s = + 1/2
Explanation:
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Answer: Na+(11 -1=10) = 1s2, 2s2,2p6
Explanation:so last electron goes to 2p so quantum number
n=2
l=1 (p)(n-1)
m= -1,0,+1 (-l to +l)
S=(+1/2), (-1/2)
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