Question

The correctness of an equation is checked

using the principle of homogeneity.

For an equation x=a+bt+ct^2

where x is in metre and t in second. What will

be the dimension of ‘b’? ​

Answer 1

Answer:

Length / time = L / t = M°LS^-1

Explanation:

According to principle of homogeneity , if the left side of equation is distance then the each term of right hand side of equation be distances seperately ,

So , bt = X

Where , X is in metre means length

and t time is in second .

So. b = X/t

b = length/time

b = L/s = LS^-1 Answer

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Hope it's helpful

Answer 2

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$\huge\boxed{\red{SOLUTION}}$

➵Let's solve for a.

➵x=a+bt+ct2

➵Step 1: Flip the equation.

➵ct2+bt+a=x

➵Step 2: Add -ct^2 to both sides

➵ct2+bt+a+−ct2=x+−ct2

➵bt+a=−ct2+x

➵Step 3: Add -bt to both sides.

➵bt+a+−bt=−ct2+x+−bt

➵a=−ct2−bt+x

➵Answer:

➵a=−ct2−bt+x

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