The corresponding perimeters of two similar triangles are 36 cm and 24 cm respectively. If one of the side of
first triangle is 12 cm then the corresponding side of the other triangle in cmis
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DE
AB
=
EF
BC
=
DF
AC
=
P
2
P
1
[∵ Ration of corresponding sides of similar triangles is equal to the ratio of their perimeters]
⇒
DE
AB
=
P
2
P
1
⇒
DE
12
=
20
30
⇒ DE=
30
12×20
cm=8cm
Hence, the corresponding side of the second triangle is 8 cm
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