Question

the cost of 15 kg tea and 17 kg coffee is RS 183 and the cost of 25kg tea and 13 kg coffee is Rs 213 what will be the the cost of 7 kg tea and 1kg coffee​

Answer 1

Answer:

$\huge{\boxed{\rm{\blue{Answer=Rs. 37.50}}}}$

Step-by-step explanation:

Given:-

The cost of 15 kg tea and 17 kg coffee is RS 183 and the cost of 25kg tea and 13 kg coffee is Rs 213 .

To find:-

what will be the the cost of 7 kg tea and 1kg coffee.

Solution:-

Let the cost of 1 kg tea be Rs. X

and the cost of 1 kg coffee be Rs. Y

Condition-l:-

The cost of 15 kg tea and 17 kg coffee is Rs.183

=>15X+17Y=183-------(1)

Condition -ll:-

the cost of 25kg tea and 13 kg coffee is Rs 213

=>25X+13Y=213-------(2)

now,(1)×5 -(2)×3=>

75X+85Y=915

75X+39Y=639

(-)

----------------------

0+46Y=276

-----------------------

=>46Y=276

=>Y=276/46

=>Y=6

Substituting the value of Y in (1)

=>15X+17(6)=183

=>15X+102=183

=>15X=183-102

=>15X=81

=>X=81/15

=>X=27/5

=>X=5.4

now

the the cost of 7 kg tea and 1kg coffee

=7(4.5)+6

=>31.5+6

=>37.5

Answer:-

The Cost of 7kg tea and 1 kg coffee is Rs. 37.5

Answer 2

.

Let cost of 1 kg tea be Rs x and cost 1 kg coffee be Rs Y.

∴ According to first conditions,

$15x + 17y = 183 \: \: \: ...(1)$

According to second condition,

$25x + 13y = 213 \: \: ..(2)$

On Solving equation (1) & (2)

$15x + 17y - 183 = 0$

$25x + 13y - 213 = 0$

$\frac{x}{17( - 213) - 13( - 183)} = \frac{y}{ - 183.25 - 15( - 213)} = \frac{1}{15.13 - 17.25}$

$⇒ \frac{x}{ - 3621 + 2379} = \frac{y}{ - 4575 + 3195} = \frac{1}{195 - 425}$

$⇒ \frac{x}{ - 1242} = \frac{y}{ - 1380} = \frac{1}{ - 230}$

$⇒x = \frac{ - 1242}{ - 230} = 5.4$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = \frac{ - 1380}{ - 230} = 6$

∴ Cost of 7 kg tea and 1 kg coffee.

$= 7x + y$

$= 7 \times 5.4 + 6$

$= 37.8 + 6$

$[answer]\huge\sf\mathbb\color{yellow} \underline{\colorbox{red}{ = Rs. 43.80}} [answer].$