The cost of 1kg of apple and 2kg of grapes on a day was found to be Rs 180 also, the cost of 4 kg of apple and 2 kg of grapes is Rs 330. represent this situation algebraically
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Let cost each kg of apples = Rs x
Cost of each kg of grapes = Rs y
The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160
So that
2 x + y = 160 … (1)
Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300
so we get
4x + 2y= 300 … (2)
Algebraic representation of situation
2 x + y = 160 … (1)
4x + 2y= 300 … (2)
To represent it graphically, we need to plot these equation on the XY coordinate system.
We can choose two values of each equation and plot it on XY coordinate system
2x +y = 160
or
y=160-2x
hope it helps u .....
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❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
Let cost each kg of apples = Rs x
Cost of each kg of grapes = Rs y
The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160
So that
2 x + y = 160 … (1)
Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300
so we get
4x + 2y= 300 … (2)
Algebraic representation of situation
2 x + y = 160 … (1)
4x + 2y= 300 … (2)
To represent it graphically, we need to plot these equation on the XY coordinate system.
We can choose two values of each equation and plot it on XY coordinate system
2x +y = 160
or
y=160-2x
hope it helps u .....
pls follow me ...
❤️❤️❤️❤️❤️❤️
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answer Rs720 of 4kg apple
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