The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by-?
Answers
Let consider chair as x and table as y
According to the question
2x + 3y = ₹ 1300…..eq 1
3x +2y = ₹ 1200……eq 2
Multiply eq 1 by 3 and eq 2 by 2
6x + 9y = ₹3900
6x + 4y = ₹2400
Now subtract eq 2 from eq 1, we get
5y = ₹1500
Y = ₹300
Now put the value in eq 2
6x +4×300 =₹ 2400
6x +1200 =₹ 2400
6x = ₹ (2400–1200)
6x = ₹1200
X = ₹ 200
Chair price = x = ₹200
Table price = y = ₹300
Ans : Cost of each table is more than that of chair
= ₹(300–200) = ₹100
Step-by-step explanation:
Let consider chair as x and table as y
According to the question
2x + 3y = ₹ 1300…..eq 1
3x +2y = ₹ 1200……eq 2
Multiply eq 1 by 3 and eq 2 by 2
6x + 9y = ₹3900
6x + 4y = ₹2400
Now subtract eq 2 from eq 1, we get
5y = ₹1500
Y = ₹300
Now put the value in eq 2
6x +4×300 =₹ 2400
6x +1200 =₹ 2400
6x = ₹ (2400–1200)
6x = ₹1200
X = ₹ 200
Chair price = x = ₹200
Table price = y = ₹300
Cost of each table is more than that of chair = ₹(300–200) = ₹100 Ans…