The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by-?
Answers
Question:-
The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by-?
Given:-
The cost of 2 chairs and 3 tables = Rs.1300
The cost of 3 chairs and 2 tables = Rs.1200
To Find:-
By how much is the cost of table more than the cost of chair.
Solution:-
Let the cost of each chair be x
And cost of each table be y
Case 1:-
Cost of 2 chairs + 3 tables = 1300
Case 2:-
Cost of 3 chairs + 2 tables = 1200
Multiply equation (i) with 3 and (ii) with 2
Equation (iii) - (iv)
Substitute y = 300 in equation (i)
Therefore:-
Cost of a chair = Rs.200
Cost of a table = Rs.300
Hence,
The cost of each table is more than that of each chair by Rs.100.
The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
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Let consider chair as x and table as y
According to the question
2x + 3y = ₹ 1300…..eq 1
3x +2y = ₹ 1200……eq 2
Multiply eq 1 by 3 and eq 2 by 2
6x + 9y = ₹3900
6x + 4y = ₹2400
Now subtract eq 2 from eq 1, we get
5y = ₹1500
Y = ₹300
Now put the value in eq 2
6x +4×300 =₹ 2400
6x +1200 =₹ 2400
6x = ₹ (2400–1200)
6x = ₹1200
X = ₹ 200
Chair price = x = ₹200
Table price = y = ₹300
Cost of each table is more than that of chair = ₹(300–200) = ₹100