The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by- ?
Answers
100 Rs
Step-by-step explanation:
let cost a chair be RS x and cost of a table be RS y.
2x + 3y = RS 1300 [ equation-1]
3x + 2y = RS 1200 [ equation-2]
multiply equation 1 by 3 and equation 2 by 2
6x + 9y = RS 3900
6x + 4y = RS 2400
now, subtract equation 1 from equation 2
6x + 9y -( 6x + 4y) = RS 3900 - RS 2400
6x + 9y - 6x - 4y = RS 1500
5y = RS 1500
y = RS 1500/5
y = RS 300
now put value of y in equation 1
2x + 3y = RS 1300
2x + 3(300 RS) = RS 1300
2x + RS 900 = RS 1300
2x = RS 1300-Rs 900
2x = RS 400
x = RS 200
so, cost of table is RS 100 more than that of chair.
hope it helps you
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Qᴜᴇsᴛɪᴏɴ ;-
✰ Tʜᴇ ᴄᴏsᴛ ᴏғ 2 ᴄʜᴀɪʀs ᴀɴᴅ 3 ᴛᴀʙʟᴇs ɪs Rs.1300. Tʜᴇ ᴄᴏsᴛ ᴏғ 3 ᴄʜᴀɪʀs ᴀɴᴅ 2 ᴛᴀʙʟᴇs ɪs Rs.1200. Tʜᴇ ᴄᴏsᴛ ᴏғ ᴇᴀᴄʜ ᴛᴀʙʟᴇ ɪs ᴍᴏʀᴇ ᴛʜᴀɴ ᴛʜᴀᴛ ᴏғ ᴇᴀᴄʜ ᴄʜᴀɪʀ ʙʏ _ ?
Lᴇᴛ,
❥︎ Mᴜʟᴛɪᴘʟʏ 3 ɪɴ ᴇǫᴜᴀᴛɪᴏɴ(1) ᴀɴᴅ 2 ɪɴ ᴇǫᴜᴀᴛɪᴏɴ(2), ᴡᴇ ɢᴇᴛ
❥︎ Now, substract ᴇǫᴜᴀᴛɪᴏɴ(b) from ᴇǫᴜᴀᴛɪᴏɴ(a), ᴡᴇ ɢᴇᴛ
╰➝ 5q = Rs.1500
╰➝ q = 1500/5
╰➝ q = Rs.300
❥︎ Now, put the value of q in equation(2)
Pʀɪᴄᴇ ᴏғ ᴄʜᴀɪʀ ɪs 'Rs.200' .
Pʀɪᴄᴇ ᴏғ ᴛᴀʙʟᴇ ɪs 'Rs.300' .
➪ Cᴏsᴛ ᴏғ ᴇᴀᴄʜ ᴛᴀʙʟᴇ ɪs ᴍᴏʀᴇ ᴛʜᴀɴ ᴛʜᴀᴛ ᴏғ ᴇᴀᴄʜ ᴄʜᴀɪʀ,