Math, asked by Gunnn246899991, 4 months ago

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?


Explanation needed!​

Answers

Answered by SweetCharm
11

 \huge \sf {\orange{\underline{\purple{\underline{Question :-}}}}}

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?

 \huge \sf {\orange {\underline {\pink{\underline{Answer :-}}}}}

Let consider chair as x and table as y

According to the question,

2x + 3y = ₹ 1300…..eq 1

3x +2y = ₹ 1200……eq 2

Multiply eq 1 by 3 and eq 2 by 2

6x + 9y = ₹3900

6x + 4y = ₹2400

Now subtract eq 2 from eq 1, we get

5y = ₹1500

Y = ₹300

Now put the value in eq 2

6x +4×300 =₹ 2400

6x +1200 =₹ 2400

6x = ₹ (2400–1200)

6x = ₹1200

X = ₹ 200

Chair price = x = ₹200

Table price = y = ₹300

Cost of each table is more than that of chair = ₹(300–200) = ₹100

{\huge{\underline{\small{\mathbb{\pink{HOPE\:HELPS\:UH :)}}}}}}

\red{\tt{sωєєтcнαям♡~}}

Answered by MissLuxuRiant
1

\huge\boxed{\fcolorbox{purple}{ink}{Answer}}

Let consider chair as x and table as y

According to the question,

2x + 3y = ₹ 1300…..eq 1

3x +2y = ₹ 1200……eq 2

Multiply eq 1 by 3 and eq 2 by 2

6x + 9y = ₹3900

6x + 4y = ₹2400

Now subtract eq 2 from eq 1, we get

5y = ₹1500

Y = ₹300

Now put the value in eq 2

6x +4×300 =₹ 2400

6x +1200 =₹ 2400

6x = ₹ (2400–1200)

6x = ₹1200

X = ₹ 200

Chair price = x = ₹200

Table price = y = ₹300

Cost of each table is more than that of chair = ₹(300–200) = ₹100

Similar questions