The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
Explanation needed!
Answers
The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
Let consider chair as x and table as y
According to the question,
2x + 3y = ₹ 1300…..eq 1
3x +2y = ₹ 1200……eq 2
Multiply eq 1 by 3 and eq 2 by 2
6x + 9y = ₹3900
6x + 4y = ₹2400
Now subtract eq 2 from eq 1, we get
5y = ₹1500
Y = ₹300
Now put the value in eq 2
6x +4×300 =₹ 2400
6x +1200 =₹ 2400
6x = ₹ (2400–1200)
6x = ₹1200
X = ₹ 200
Chair price = x = ₹200
Table price = y = ₹300
Cost of each table is more than that of chair = ₹(300–200) = ₹100
Let the price of one chair be x rs ... meaning 1chair price = x and of table be y.
So by following conditions
2 chairs price + 3 tables price = 1300rs
So chair price is x and table price is y we can say
2x + 3y = 1300... eqn1
Similarly for anoeqn
3x + 2y = 1200... eqn2
Subtraction of eqn 1 from 2nd
Follow attachment for subtraction... and then addition
So, chairs price be ₹200 and table price be ₹300