Question

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by-?​

Answer 1

Given:-

The cost of 2 chairs and 3 tables = Rs.1300

The cost of 3 chairs and 2 tables = Rs.1200

To Find:-

By how much is the cost of table more than the cost of chair.

Solution:-

Let the cost of each chair be x

And cost of each table be y

Case 1:-

Cost of 2 chairs + 3 tables = 1300

$\sf \implies 2x + 3y = 1300.....(i)$

Case 2:-

Cost of 3 chairs + 2 tables = 1200

$\sf \implies 3x + 2y = 1200.....(ii)$

Multiply equation (i) with 3 and (ii) with 2

$\sf \implies 3(2x + 3y = 1300)$

$\sf \implies 6x + 9y = 3900......(iii)$

$\sf \implies 2(3x + 2y = 1200)$

$\sf \implies 6x + 4y = 2400......(iv)$

Equation (iii) - (iv)

$\sf \implies 6x + 9y - (6x + 4y)= 3900 - 2400$

$\sf \implies 6x + 9y - 6x - 4y= 1500$

$\sf \implies 5y = 1500$

$\sf \implies 5y = \dfrac{1500}{5} = 300$

Substitute y = 300 in equation (i)

$\sf \implies 2x + 3y = 1300$

$\sf \implies 2x + 3(300) = 1300$

$\sf \implies 2x = 1300 - 900$

$\sf \implies 2x = 400$

$\sf \implies x = 200$

Therefore:-

Cost of a chair = Rs.200

Cost of a table = Rs.300

Hence,

The cost of each table is more than that of each chair by Rs.100

Answer 2

Answer:

Given:-

The cost of 2 chairs and 3 tables = Rs.1300

The cost of 3 chairs and 2 tables = Rs.1200

To Find:-

By how much is the cost of table more than the cost of chair.

Solution:-

Let the cost of each chair be x

And cost of each table be y

Case 1:-

Cost of 2 chairs + 3 tables = 1300

\sf \implies 2x + 3y = 1300.....(i)⟹2x+3y=1300.....(i)

Case 2:-

Cost of 3 chairs + 2 tables = 1200

\sf \implies 3x + 2y = 1200.....(ii)⟹3x+2y=1200.....(ii)

Multiply equation (i) with 3 and (ii) with 2

\sf \implies 3(2x + 3y = 1300)⟹3(2x+3y=1300)

\sf \implies 6x + 9y = 3900......(iii)⟹6x+9y=3900......(iii)

\sf \implies 2(3x + 2y = 1200)⟹2(3x+2y=1200)

\sf \implies 6x + 4y = 2400......(iv)⟹6x+4y=2400......(iv)

Equation (iii) - (iv)

\sf \implies 6x + 9y - (6x + 4y)= 3900 - 2400⟹6x+9y−(6x+4y)=3900−2400

\sf \implies 6x + 9y - 6x - 4y= 1500⟹6x+9y−6x−4y=1500

\sf \implies 5y = 1500⟹5y=1500

\sf \implies 5y = \dfrac{1500}{5} = 300⟹5y=

5

1500

=300

Substitute y = 300 in equation (i)

\sf \implies 2x + 3y = 1300⟹2x+3y=1300

\sf \implies 2x + 3(300) = 1300⟹2x+3(300)=1300

\sf \implies 2x = 1300 - 900⟹2x=1300−900

\sf \implies 2x = 400⟹2x=400

\sf \implies x = 200⟹x=200

Therefore:-

Cost of a chair = Rs.200

Cost of a table = Rs.300

Hence,

The cost of each table is more than that of each chair by Rs.100