The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
Answers
Step-by-step explanation:
Let consider chair as x and table as y
According to the question
2x + 3y = ₹ 1300…..eq 1
3x +2y = ₹ 1200……eq 2
Multiply eq 1 by 3 and eq 2 by 2
6x + 9y = ₹3900
6x + 4y = ₹2400
Now subtract eq 2 from eq 1, we get
5y = ₹1500
Y = ₹300
Now put the value in eq 2
6x +4×300 =₹ 2400
6x +1200 =₹ 2400
6x = ₹ (2400–1200)
6x = ₹1200
X = ₹ 200
Chair price = x = ₹200
Table price = y = ₹300
Cost of each table is more than that of chair = ₹(300–200) = ₹100 Ans…
Solution without equations
3 chair & 2 table costs Rs 1300 &
2 chairs & 3 tables cost Rs 1200
=> 5 chairs & 5 table costs Rs 2500
=> 1 table & 1 chair costs Rs 500
=> 1 table costs Rs 300
=> each chair costs Rs 200
=> each table costs Rs 100 more than chair.
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Let cost of a chair is Rs x and cost of a table is Rs y ,acordingly:-
2x+3y=1300………………..(1)
3x+2y=1200………………….(2)
x/(3600–2600)=y/(3900–2400)=-1/(4–9).
x/1000=y/1500=1/5.
x=1000/5 = 200.
y=1500/5 = 300
Difference in cost of a table and a chair =y-x = 300–200 = Rs 100. Answer.
3 chairs and 2 tables costs Rs.700 and 5 chairs and 3 tables costs Rs. 1100. What is the cost of 2 chairs and 2 tables?
If 2 tables and 3 chairs cost Rs, 3500 and 3 tables and 2 chairs cost Rs. 4000, then how much does a table cost?
Two chair and three table cost Rs.1025 and three chairs and two tables cost Rs. 1100. What is the difference between the cost of one table and that of one chair?
let, cost of chairs= x
cost of tables = y
2x+3y=1300
3x+2y=1200
on solving both eqn
x=200
y=300
300–200=100
cost of each table is more than that of chair by 100