Question

The cost of 2 jeans and 3 jackets is rs 11000. if the cost of jeans rs 500 more than the jacket, find the cost of jeans and jackets

Answer 1

Let cost of jacket=x

Then cost of jean=x+500

So we have 2 jeans and 3 jackets

3x+2(x+500)=11000

3x+2x+1000=11000

5x=11000-1000

5x=10000

X=10000/5=2000

Cost of one jacket =2000

Cost of 3 jackets=2000x3=6000

Cost of 1 jean=2000+500=2500

Cost of 2 jeans =2500x2=5000


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Answer 2

let cost of jeans be a
and cost of jacket be b
a/q
2a + 3b =11000. eq(1)
a-b=500 .eq(2)

eq(1)+3eq(2)
2a+3b+3a-3b=12500
=>5a=12500
=>a=2500
putting a=2500 in eq(2)
2500-b=500
b=2000
the cost of 1 jeans=2500
the cost of 1 jacket=2000