Question

the cost of 2 kg apples and 1 kg grapes on a day was found to be 760 rupees after a month the cost of 4 kg of apples and 2 kg of grapes is 300 rupees cheaper than the situation algebraic and geometrical

Answer 1

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Let cost each kg of apples  = Rs x

Cost of each kg of grapes  = Rs  y

 Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160

So that

2 x +  y  = 160             … (1)

2x          = 160  - y

x            = (160 – y)/2

Let y = 0 , 80  and 160  we get

x = (160 – ( 0 ))/2   =  80

x = (160- 80 )/2      = 40

x = (160 – 2* 80 )/2 = 0

X

80

40

0

y

0

80

160


Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300

so we get

4x +  2y= 300             … (2)

Divide by 2 we get

2x + y   = 150

Subtract 2x both side we get

y        = 150 – 2 x

Plug  x = 0 , 50 , 100  we get

y        = 150 – 2*0               = 150

y        = 150 – 2* 50             =  50

y        = 150 – 2 * (100 )      = - 50


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