The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.
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Answers
Answer:
x 65 55 45 35
y 20 40 60 80
Let the cost of 1 kg of apples be x and that of 1 kg be y
So the algebraic representation can be as follows:
2x+y=160
4x+2y=300⇒2x+y=150
The situation can be represented graphically by plotting these two equations.
2x+y=160⇒y=160−2x
x 70 60 50 40
y=160−2x 20 40 60 80
2x+y=150⇒y=150−2x
x 65 55 45 35
y=150−2x 20 40 60 80
We can see that the lines do not intersect anywhere, i.e. they are parallel. Hence we can not arrive at a solution.
Thank you so much
Explanation:
x 65 55 45 35
y 20 40 60 80
Let the cost of 1 kg of apples be x and that of 1 kg be y
So the algebraic representation can be as follows:
2x+y=160
4x+2y=300⇒2x+y=150
The situation can be represented graphically by plotting these two equations.
2x+y=160⇒y=160−2x
x 70 60 50 40
y=160−2x 20 40 60 80
2x+y=150⇒y=150−2x
x 65 55 45 35
y=150−2x 20 40 60 80