Question

The cost of 2 kg of apples and 1kg of grapes on a day was found to be * 160. After a
month, the cost of 4 kg of apples and 2 kg of grapes is 300. Represent the situation
algebraically and geometrically.​

Answer 1

2x+y=160---(1eqn.)

4x+2y=300---(2nd eqn.)

2x=160-y (from 1st eqn.)

x=160-y÷2

Now put the value of x in 2nd eqn.

4[160-y/2]+2y=300

4[160-y/2+2y]=300

now take tha LCM in bracket.

4[160-y+4y/2]=300

4[160+3y/2]=300

Cut the 4 by 2 which is in divide

2[160+3y]=300

320+6y=300

6y=300-320

y=-20/6

y=-10/3 now put this value in 1st eqn

Answer 2

Let the cost of 1 kg of apples be ‘Rs. x’

And, cost of 1 kg of grapes be ‘Rs. y’

According to the question, the algebraic representation is

2x+y = 160

And 4x+2y = 300

For, 2x+y = 160 or y = 160−2x