Question

The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically and geometrically.
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Answer 1

Answer:-

Let the cost of Apples per kg be Rs. x.

and let the cost of grapes per kg be Rs. y.

Given that,

2 kg apples and 1 kg grapes cost Rs. 160

2 x Cost per kg of apples + 1 x Cost per kg of grapes = 160

 2x + y = 160 .... (1)

Also, 4 kg apples and 2 kg grapes cost Rs. 300

4 x Cost per kg apples + 2 x Cost per kg of grapes = 300

4x + y = 300

2 (2x + y)  = 2 x 150

2x+y = 150....(2)

Now, plotting equations

2x+y = 160...(1)

2x+y = 150....(2)

For equation (1)

2x +y = 150

2x+y = 150

x = 50    60

y = 50    30

Let x =  50

2(50) + y = 150

100 + y = 150

y = 150 - 100

y = 50

So, x= 50, y = 50 is the solution

(i.e. 50, 50 is a solution)

Let x = 60

2(60) + y = 150

120 + y = 150

y = 150 - 120

y = 30

So, x= 60, y = 30 is the solution

(i.e. 60, 30 is a solution)

For equation (2)

2x + y = 160

x = 50  60

y = 60   40

Let x = 50

2(50) + y = 160

100 + y = 160

y = 160 - 100

y = 60

So, x = 50, y = 60 is the solution

i.e. (50,60) is a solution

Let x = 60

2(60) + y = 160

120 + y = 160

y = 160 - 120

y = 40

So, x = 60, y = 40 is the solution

i.e. (60, 40) is a solution

2x + y = 150

x = 50  60

y = 50   30

2x + y = 160

x = 50  60

y = 60   40

Explanation:-

Hope it helps. Please mark as brainliest.

Answer 2

Answer:

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Explanation:

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