Question

The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically.

Answer 1

y 20 40 60 80

Let the cost of 1 kg of apples be x and that of 1 kg be y

So the algebraic representation can be as follows:

2x+y=160

4x+2y=300⇒2x+y=150

The situation can be represented graphically by plotting these two equations.

2x+y=160⇒y=160−2x

x 70 60 50 40

y=160−2x 20 40 60 80

2x+y=150⇒y=150−2x

x 65 55 45 35

y=150−2x 20 40 60 80

We can see that the lines do not intersect anywhere, i.e. they are parallel. Hence we can not arrive at a solution.

solution

Answer 2

Answer:

Let the cost of 1 kg of apples be ‘Rs. x’.

And, let the cost of 1 kg of grapes be ‘Rs. y’.

According to the question, the algebraic representation is :-

2x + y = 160

And 4x + 2y = 300

For, 2x + y = 160 or y = 160 − 2x, the solution table is;

Tables are in the attachment