the cost of 2 tables and 3 chair is rupees 705 if the table cost rupees 35 more than the chair find the cost of the table and the chair
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let the cost of one table=x
the cost of one chair=y
2x+3y=705......(1)
x-y=35....(2)
Elimination method
2x+3y=705
3x-3y=105
5x=600
x=120
put value of x in eq2
120-35=y
y=85
the cost of one table is 120rs & one chair is 85rs
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