Question

the cost of 2 tables and 3 chairs is Rs. 705. if the table costs Rs.40 more than the chair, then sum of the digits of the cost of the table is..........

Answer 1

Hi, here's correct answer for your question.
Let the cost of table be x and that of chair be y.
So,the equations are,
2x+3y=705-------(1)
x=y+40------------(2)
Substituting (2) in (1),
2(y+40)+3y=705
2y+80+3y=705
5y=705-80
5y=625
y=625/5
y=125---------(3)
Substituting (3) in (2),
x=125+40
x=165
So,the value of table is Rs.165 and that of chair is Rs.125.
Sum of the digits of cost of table=1+6+5=12
Thank you.
Mark it as brainliest if you like.

Answer 2

Hey

Here is your answer,

cost of chair assume it as rupees x and table as x+40.

no of tables 2 and no of chairs 3.total cost = Rs.705
2 tables + 3 chairs = Rs.705

2[x+40]+3x=705
2x+80+3x=705
5x+80=705
5x=705-80
5x=625
x=625/5
x=125

cost of chair=x=Rs.125

cost of table=x+40=125+40=Rs.165

Sum of digits of cost of table = 1+6+5=12.

Hope it helps you!