The cost of 2kg apples and 1 kg of grapes on a day was found to be 160 after a month the cost of 4kg of apples and 2 kg of grapes is 300 represent it algebrically and graphically
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Let the cost of 1kg of apples be x and cost of 1 kg of grapes be y
Then the algebraic representation
2x + y = 160 .................... (Eqn 1)
4x + 2y = 300 ........................(Eqn 2)
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Let cost of 1 kg of apples = Rs x
Let cost of 1 kg of grapes= Rs y
According to given conditions, we have
2x+y=160 (1)
4x+2y=300
⇒2x+y=150 (2)
So, we have equations (1) and (2)
2x+y=160 and 2x+y=150 which represent given situation algebraically.
To represent them graphically, we will find 3 sets of points which lie on the lines.
We plot the points for both of the equations and it is the graphical representation of the given situation.
2x+y=160 and 2x+y=150
Let cost of 1 kg of grapes= Rs y
According to given conditions, we have
2x+y=160 (1)
4x+2y=300
⇒2x+y=150 (2)
So, we have equations (1) and (2)
2x+y=160 and 2x+y=150 which represent given situation algebraically.
To represent them graphically, we will find 3 sets of points which lie on the lines.
We plot the points for both of the equations and it is the graphical representation of the given situation.
2x+y=160 and 2x+y=150
Attachments:
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