The cost of 2kg apples and 1 kg of grapes on a day was found to be 160 after a month the cost of 4kg of apples and 2 kg of grapes is 300 represent it algebrically and graphically
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Let the cost of 1kg of apples be x and cost of 1 kg of grapes be y
Then the algebraic representation
2x + y = 160 .................... (Eqn 1)
4x + 2y = 300 ........................(Eqn 2)
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et cost each kg of apples = Rs x
Cost of each kg of grapes = Rs y
Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160
So that
2 x + y = 160 … (1)
2x = 160 - y
x = (160 – y)/2
Let y = 0 , 80 and 160 we get
x = (160 – ( 0 ))/2 = 80
x = (160- 80 )/2 = 40
x = (160 – 2* 80 )/2 = 0
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