the cost of 3 biscuits and 5 chocolates is ₹385. if the cost of the chocolate is ₹5 more than the cost of the biscuits, find the cost of both the items.
Answers
Answer:
The cost of 3 chocolates, 5 biscuits, and 5 ice creams is 195. What is the cost of 7 chocolates, 11 biscuits and 9 ice creams?
(1) The cost of 5 chocolates, 7 biscuits and 3 ice creams is 217.
(2) The cost of 4 chocolates, 1 biscuit and 3 ice creams is 141.
Given:
3C+5B+5IC=1953C+5B+5IC=195
7C+11B+9IC=?7C+11B+9IC=?
if we subtract the two equations, we'll get
4C+6B+4C4C+6B+4C;2(2C+3B+2C)2(2C+3B+2C). so if we know this value, we can find the total cost.
statement 1:
5C+7B+3IC=2175C+7B+3IC=217. add this to given equation
(5C+3C)+(7B+5B)+(3IC+5IC)=(217+195)(5C+3C)+(7B+5B)+(3IC+5IC)=(217+195)
8C+12B+8IC=5228C+12B+8IC=522; 4(2C+3B+2C)=5224(2C+3B+2C)=522
knowing the value of (2C+3B+2C)(2C+3B+2C) is sufficient to calculate 7C+11B+9IC7C+11B+9IC.
statement 2:
4C+1B+3IC=1414C+1B+3IC=141
this is not sufficient.
even if we add this equation with the given equation, we get
7C+6B+8IC7C+6B+8IC, so we still the value of 5B+IC=?5B+IC=?.
not sufficient
Ans: A