Math, asked by gachalife99, 7 hours ago

The cost of 3 Kg of apples and 2 Kg of grapes on a day was found to be Rs. 510. After a month, the cost of 4 Kg of apples and 1 Kg of grapes is Rs. 680. Represent the situation algebraically.

Answers

Answered by llchummill
0

Answer:

ns in two variables.

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Answer

Let rate of apples =x Rs/kg

Let rate of grapes =y Rs/kg

Now according to question

3x+2y=160

4x+2y=300

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Answer

Answered by Anonymous
2

Let,

the Cost of Apples per kg = Rs x.

& the Cost of grapes per kg = Rs y.

Given,

2 kg apples and 1 kg grapes cost Rs 160.

2 x Cost per kg of apples + 1 x Cost per kg of grapes = 160

2x + y = 160 ...(1)

Also,

4 kg apples and 2 kg grapes cost Rs 300

4 x Cost per kg of apples + 2 x Cost per kg of grapes = 300

4x + 2y = 300

2(2x + y) = 2 x 150

2x + y = 150... (2)

Now, plotting equations

2x + y = 160...(1)

2x + y = 150...(2)

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