The cost of 3 kg of apples and 2 kg of grapes on a day was found to be ₹160.After a month the cost of 4 kgs of apples and 2 kg of grapes is ₹300. Represent the situation as a pair of linear equations in two variables.
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Answered by
10
Let the cost of apples per kg be Rs x
Let the cost of grapes per kg be y
2 kg apples and 1 kg grapes cost rs 160
2 × cost per kg of apples+1× cost per kg of graped
2x + y = 160
2x + y - 160 = 0
Also 4 kg apples and 2 kg grapes cost rs 300
4 × cost per kg of apples +2 × cost per kg of grapes = 300
4x + 2y = 300
4x + 2y - 300 = 0
2(2x + y - 150 ) = 0
(2x + y - 150 ) = 0/2 = 0
Let the cost of grapes per kg be y
2 kg apples and 1 kg grapes cost rs 160
2 × cost per kg of apples+1× cost per kg of graped
2x + y = 160
2x + y - 160 = 0
Also 4 kg apples and 2 kg grapes cost rs 300
4 × cost per kg of apples +2 × cost per kg of grapes = 300
4x + 2y = 300
4x + 2y - 300 = 0
2(2x + y - 150 ) = 0
(2x + y - 150 ) = 0/2 = 0
Answered by
3
let x be the no of apples and y be the number of grapes.then;
Given that;3x+2y=160
the next one after a month;4x+2y=300
Given that;3x+2y=160
the next one after a month;4x+2y=300
deepika625:
it is 1m question so no need of deep explanation
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