Question

The cost of 3 kg of apples and 2 kgs of grapes on a day was found to be Rs.350. After a month cost of 4 kg of apples and 3 kg of grapes was found to be Rs.450.Represent this situation algebraically to find the cost of apple and grape.. find the correct option please it's urgent

3x + 2y = 350 ; 4x + 3y = 450

5x = 350 ; 7x = 450

3x + 2y = 350 ; 4(x+1) + 3(y+1) = 450

3x + 2y = 350 ; 3x + 4y = 450​

Answer 1

Answer:

3x + 2y = 350 ; 4x + 3y = 450

Step-by-step explanation:

In this question, we must make an algebraic formula for the situation given.

Let's start by assigning:

apples = x

grapes = y

I have assigned this according to the questions and the options.

Month 1:

3kg apples = 3x

2kg grapes = 2x

Total cost = Rs.350

Therefore, the equation will be: 3x + 2y = 350

Month 2:

4k apples = 4x

3kg grapes = 3x

Total cost = Rs.450

Therefore, the equation will be 4x + 3y = 450

Thus, the final answer will be 3x + 2y = 350 ; 4x + 3y = 450

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