Math, asked by sidhu012, 16 hours ago

The cost of 30 flats was 60 lakh each. A builder sold 1/3 of the flats at 15% profit and 1/6 of the flats at 6% loss. If he suffers a net loss of 10% after selling the remaining flats, then what was his loss percentage in the remaining flats?​

Answers

Answered by maangurpreet183
3

Answer:

Step-by-step explanation:

14.3 ans

Answered by amitnrw
2

Given : The cost of 30 flats was 60 lakh each.

A builder sold 1/3 of the flats at 15% profit and

1/6 of the flats at 6% loss.

He suffers a net loss of 10% after selling the remaining flats,  

To Find :  his loss percentage in the remaining flats

Solution:

Cost of 1 flat = 30 Lakhs

Cost of 60 flats = 60 * 30  =  1800 Lakhs

a net loss of 10%  = (10/100) 1800 = 180 lakhs

Net sell Price = 1800 - 180  = 1620 Lakhs

sold 1/3 of the flats at 15% profit and

=> Flats = (1/3) * 30 = 10

Selling price = 60 + (15/100)60 = 69 lakhs

Selling price of 10 flats = 10 * 69 = 690 lakhs

1/6 of the flats at 6% loss.

=> Flats = (1/6) * 30 = 5

Selling price = 60 - (6/100)60 = 56.4 lakhs

Selling price of  5  flats = 5 * 56.4 = 282 lakhs

Remaining Flats = 30 - 10 - 5  = 15

Remaining Flats sold in = 1620  - 690 - 282   =  646 lakhs

Remaining flats costs = 15 * 60 = 900 lakhs

Loss = 900 - 646  = 254 lakhs

Loss %  = (254/900) * 100  = 254/9 %  =  28.22 %

his loss percentage in the remaining flats   =  28.22 %

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