Question

the cost of 4 chairs and 3 tables is rs2100 and the cost of 5 chairs and 2 tables is rs 1750 find the cost of one chair and one table separately

Answer 1

Let cost of table be X
and cost of chair be y
then 4y+3x=2100
5y+2x=1750
--------------------------

1st eqn ×2=8y+6x=4200
2nd eqn×3=15y+6x=5250
--------------------------------------------
1st eqn _2nd eqn-7y=-1050
therefore y=150 Rs
when sub y in eqn 4y+3x=2100
4×150+3x=2100 there fore3x=2100_600
x=1500÷3=500rs

Answer 2

Let,
Cost of 1 chair = Rs.x

Cost of 1 table = Rs.y

According to 1st case,

Rs.(4x + 3y) = Rs.2100

=> 4x + 3y = 2100


According to 2nd case,

Rs.(5x + 2y) = Rs.1750

=> 5x + 2y = 1750


(1) => 4x + 3y = 2100

=> 3y = 2100 - 4x

=> y = 2100 - 4x/3

(2)=> 5x + 2(2100 - 4x/3) = 1750

=> 15x+4200-8x/3 = 1750

=>7x +4200 = 1750 × 3

=>7x = 5250 - 4200

=> 7x = 1050

=>x=1050/7

=>x = 150


(3) => y = 2100-4x/3

=>y = 2100-4×150/3

=>y = 2100-600/3

=>y = 1500/3

=>y = 500

•°• Cost of one chair =Rs.150

Cost of one table = Rs.500