Question

The cost of 5 orange and 3 apple is rupees 35 and the cost of 2 orange and 4 apple is 28.find the cost of 3 orange and 3 apple​

Answer 1

Step-by-step explanation:

let the cost of orange be x and apple be y

:5x + 3y = 35 ------(1)

therefore, 2x + 4y = 28 ------(2)

multiple (1) by 2 and (2) by 5 and substrate

10x + 6y - ( 10x + 20y ) = 70 - 140

10x + 6y - 10x - 20y = -70

-14y = - 70

y = 5

put y = 5 on (1)

5x + 3 × 5 = 35

5x + 15 = 35

5x = 20

x = 4

the cost of 3 orange and 3 apple

3x + 3y

3 × 4 + 3 × 5

12 + 15

27

Answer 2

Answer:

Cost of 3 orange and 3 apple is 27

Step-by-step explanation:

Given

the cost of 5 oranges and 3 apples : 35Rs

=> 5x + 3y = 35........(1)

the cost of 2 oranges and 4 apples : 28Rs

=> 2x + 4y = 28.........(2)

let us take X as orange and y as apple

let's solve...

Solution

2x + 4y = 28

2x = 28 - 4y

x = (28 - 4y)/2

x = 14 - 2y

(substitution method)

in 1st equation

(14 - 2y)5 + 3y = 35

70 - 10y + 3y = 35

70 - 35 = 10y - 3y

35 = 7y

y = 35/7

y = 5

equation (2)

substituting y to find X

2x + 4(5) = 28

2x = 28 - 20

2x = 8

x = 8/2

x = 4

Now cost of 3 oranges and 3 apples

=3x + 3y

=3(5) + 3(4)

=15 + 12

=27