Question

The cost of 5 oranges and 3 apples is 35 and the cost of 2 oranges and 4 apples is 28.Find the total cost of 6 oranges and 4 apples

Answer 1

$\bold{Let \: \: the \: \: cost \: \: of \: \: orange \: \: be \: \: x \: \: \: And \: \: cost \: \: of \: \: apple \: \: be \: \: y }$


According to the question,


5x + 3y = 35 -----: ( 1 ) equation

2x + 4y = 28 ----: ( 2 ) equation




Multiply ( 1 ) equation by 2 and ( 2 ) equation by ( 5 ) , After that subtract the formed equation,


[ 5x + 3y = 35 ] × 2
[ 2x + 4y = 28 ] × 5




Hence, it will like,

10x + 6y = 70
10x + 20y = 140
-__(-)____(-)___
-14y = - 70
____________

14 y = 70

$y = \frac{70}{14} \\ \\ y = 5$


Putting the value of y in 1equation,


5x + 3y = 35

=> 5x = 35 - 3( 5 )

=> 5x = 35 - 15

=> x = 20 / 5

=> x = 4





Hence, cost of one Orange = x = ₹4
Cost of one apple = y = ₹5




Due to which, cost of 6 oranges + 4 apples

=>6( 4 ) + 4( 5 )

=> 24 + 20

=> ₹44

Answer 2

hey there!!

let us take the cost of 1 orange as 'x'

let us take the cost of 1 apple as 'y'

Then,

5x + 3y = 35

AND,

2x + 4y = 28

_____________________________

5x + 3y = 35 ------------------ (1)
2x + 4y = 28 ------------------ (2)

Let's multiply the the 1st equation with 4 and the 2nd equation with 3

we get,

20x + 12y = 140
6x + 12y = 84

Lets subtract,

we get,

14x = 56

x = 56/14

x = 4

the cost of one orange is 4

let's substitute,

24 + 12y = 84

12y = 60

y = 60/12

y = 5

The cost of one apple is 5

The cost of 6 oranges and 4 apples is,

(6)(4) + (5)(4)

= 24 + 20

= 44 rupees

Hope my answer helps! : )