Question

The cost of 8 oranges and 5 apples is Rs 90 and the cost of 2 oranges and 1
apples is Rs 20.
Q 1. The algebraic representation of the first condition is
84-5yA50
84+5yA90
Q 2. The algebraic representation of the second condition is
24+yA20
2y+4A20
Q I. The cost of an orange is
Rs 5
Rs 8

Answer 1

Step-by-step explanation:

Let the cost of an orange =Rsx

And the cost of an apple =Rsy

According to the question,

5x+3y=35

And 2x+4y=28

⇒x+2y=14

By cross-multiplication method, we have

⇒

−42+70

x

=

−35+70

y

=

10−3

1

⇒

28

x

=

35

y

=

7

1

I II III

On taking I and III ratio, we get

⇒

28

x

=

7

1

⇒x=4

On taking II and III ratio, we get

⇒

35

y

=

7

1

⇒y=5

Hence, the cost of an orange is Rs. 4 and cost of an apple is Rs. 5

Answer 2

Answer:

rupees 5 is the cost of orange