Question

the cost of 8 pens and 4 pencils is rs.176 and the cost of 2 pens and 2 pencils is 48 . what is the cost of one pen?​

Answer 1

Answer:

Step-by-step explanation:

Let the cost price of 1 pen be Rs.x and that of 1 pencil be Rs.y.

8x + 4y = 176 ....(i)

and 2x + 2y = 48

=> x + y = 24 => y = 24 - x

Pulling this value in equation (i)

8x + 4 (24-x)= 176

=> 8x - 4x= 176 - 96

=> 4x = 80

=>x=804=20

CP of 1 pen = Rs.20

Answer 2

Answer:

Here, Cost of one pen is ₹20.

Step-by-step explanation:

Here, As per our given question,

Let cost of 1pen be x and cost of 1pencil be y,

=Cost of 8pens and 4pencils=₹176

So, 8x+4y=176 -(1st)eq.

Now, For 2nd time,

=Cost of 2pens and 2pencils=₹48

So, 2x+2y=48 -(2nd)eq.

Now, On solving both equations by elimination method, We would multiply with 1 in eq. 1 and with 2 in eq. 2,and then subtract 2nd eq. from 1st eq.,

=8x+4y=176

=4x-4y=96

After solving it, we get,

=8x-4x=176-96

=4x=80

=x=80/4

=x=20

Now, by putting the value of x in eq. 1,we get,

=8×(20)+4y=176

=160+4y=176

=4y=176-160

=4y=16

=y=16/4

=y=4

Now, As we get after solving the equations, we have, Cost of 1pen=₹20

Cost of 1pencil=₹4

Now, Proof:

=8x+4y=176

=8×20+4×4=176

=160+16=176

=176=176

LHS=RHS

Hence, Proved.

Thank you.