the cost of 9 chairs and 3 tables is Rs 306 while the cost of 8 chairs and 2 tables is Rs 256,then the cost of 6 chairs and 1 table will be?
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Let the cost of 1 chair be x and the table be y.
Case 1
9x + 3y= 306
3x+ y = 102
3x = 102-y
x. = (102 - y)/3 (1)
Case 2
8x + 2y = 256
4x+ y = 128 (2)
Putting the value of x in eq 2 we get
4(102 - y) /3 + y = 128
(408 - 4y + 3y) /3 = 128
408 - y = 384
y = 24
Putting the value of y in eq 1 we get
x = 39
Therefore, the cost of 6 chair = 234
And cost of 1 table = 24
Case 1
9x + 3y= 306
3x+ y = 102
3x = 102-y
x. = (102 - y)/3 (1)
Case 2
8x + 2y = 256
4x+ y = 128 (2)
Putting the value of x in eq 2 we get
4(102 - y) /3 + y = 128
(408 - 4y + 3y) /3 = 128
408 - y = 384
y = 24
Putting the value of y in eq 1 we get
x = 39
Therefore, the cost of 6 chair = 234
And cost of 1 table = 24
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