Math, asked by shinna, 1 year ago

the cost of a car purchased 2 year ago depreciates at the rate of 20% every year if its present value is 252480 rupees find.

1. purchase price
2.its value after 1 year

Answers

Answered by Draxillus
36
hey dear,

ur answer goes like this:-

--------------->>>>>>>>>>>>>>>---------------

let the cost of car two years ago was Rs 'x'.

now,

A/Q,

its cost depriciates at the rate of 20% every year.

So,price after two years from two years ago.

A = p (1 - r/100)²

252480 = p (1 - 20/100)²

=>252480 = p (4/5)²

=>p = 252480 × 25/16

=>p = 394500 Ans.

Thus,purchase price = Rs 394500.

Again,

current price = Rs.252480

So,price after two years from now

= 254280(1 -20/100)¹

= 254280(4/5)

=Rs.201984 Ans.

------------------>>>>>>>>>>>>>-------------


Learn the formula please:-

in case of depreciation,price after n years at the rate of r℅ =

p (1 - r/100) ^n

---------------->>>>>>>>>>>>-----------------


Thanks

@EVERkshitijEST





shinna: thanx friend
shinna: friend 252480 = p(1-20/100) how it come to p(4/5)
Draxillus: 20/100 = 1/5
Draxillus: N⃗o⃗w⃗, 1 - 1/5 = 5-1/5 = 4/5
Draxillus: ι нσρє υ υи∂єяѕтσσ∂ ѕιѕ
shinna: yes sure
Draxillus: thanks sis
Answered by MeghaAnushka
0

Answer:

This is your answer. I'm not sure that this is correct. You can check the answer from the back of your book if there are answers. But I hope it helps you.

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