the cost of a car purchased 2 year ago depreciates at the rate of 20% every year if its present value is 252480 rupees find.
1. purchase price
2.its value after 1 year
Answers
Answered by
36
hey dear,
ur answer goes like this:-
--------------->>>>>>>>>>>>>>>---------------
let the cost of car two years ago was Rs 'x'.
now,
A/Q,
its cost depriciates at the rate of 20% every year.
So,price after two years from two years ago.
A = p (1 - r/100)²
252480 = p (1 - 20/100)²
=>252480 = p (4/5)²
=>p = 252480 × 25/16
=>p = 394500 Ans.
Thus,purchase price = Rs 394500.
Again,
current price = Rs.252480
So,price after two years from now
= 254280(1 -20/100)¹
= 254280(4/5)
=Rs.201984 Ans.
------------------>>>>>>>>>>>>>-------------
Learn the formula please:-
in case of depreciation,price after n years at the rate of r℅ =
p (1 - r/100) ^n
---------------->>>>>>>>>>>>-----------------
Thanks
@EVERkshitijEST
ur answer goes like this:-
--------------->>>>>>>>>>>>>>>---------------
let the cost of car two years ago was Rs 'x'.
now,
A/Q,
its cost depriciates at the rate of 20% every year.
So,price after two years from two years ago.
A = p (1 - r/100)²
252480 = p (1 - 20/100)²
=>252480 = p (4/5)²
=>p = 252480 × 25/16
=>p = 394500 Ans.
Thus,purchase price = Rs 394500.
Again,
current price = Rs.252480
So,price after two years from now
= 254280(1 -20/100)¹
= 254280(4/5)
=Rs.201984 Ans.
------------------>>>>>>>>>>>>>-------------
Learn the formula please:-
in case of depreciation,price after n years at the rate of r℅ =
p (1 - r/100) ^n
---------------->>>>>>>>>>>>-----------------
Thanks
@EVERkshitijEST
shinna:
thanx friend
Answered by
0
Answer:
This is your answer. I'm not sure that this is correct. You can check the answer from the back of your book if there are answers. But I hope it helps you.
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