)The cost of A item is increased by 10% and the cost of item B is increased by 18%. Before the price rise, the ratio of the cost of the item A to the cost of the item B was 9 : 2. If the cost of 12 A items and 54 B items before the price rise was Rs C, what is their cost (in Rs) now?
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Before price rise:
Let us consider that, the cost of
- A item is Rs. x
- B item is Rs. y
Given:
- x : y = 9 : 2
- or, x/y = 9/2
- or, 2x = 9y ..... (i)
Also given, cost of 12 A items + cost of 54 B items = Rs. C
Then, 12x + 54y = C ..... (ii)
Putting 2x = 9y in (ii), we get
6 (9y) + 54y = C
or, 54y + 54y = C
or, 108y = C
or, y = C/108
So, x = C/24
After price rise:
Cost of A item is increased by 10%.
Then present cost is
= Rs. x * (1 + 10/100)
= Rs. 11x/10
= Rs. 11/10 * C/24
= Rs. 11C/240
Cost of B item is increased by 18%.
Then present cost is
= Rs. y * (1 + 18/100)
= Rs. 59y/50
= Rs. 59/50 * C/108
= Rs. 59C/5400
Answer: Therefore their present cost -
- for A item is Rs. 11C/240 and
- for B item is Rs. 59C/5400.
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