The cost of a machine is 9000. If the cost decline is 10% of the cost at the beginning of each year then what will be the cost of the machine 3 years later
Answers
cost of machine is 9000
decline 10% of the cost every year
10% of 9000= 10/100 ×9000
= 900
1 year 9000-900=₹8100
10% of 8100= 10/100×8100
=810
2 year 8100-810=₹7290
10% of 7290=10/100×7290
=729
3 year 7290-729=₹6561
cost after 3 year is ₹6561
The require answer is 6561 rs.
As per the question we need to find the cost of the machine 3 years.
cost of machine is 9000
decline 10% of the cost every year
10% of 9000= 10/100 ×9000
= 900
1 year 9000-900=₹8100
10% of 8100= 10/100×8100
=810
2 year 8100-810=₹7290
10% of 7290=10/100×7290
=729
3 year 7290-729=₹6561
cost after 3 year is ₹6561
Hence the require answer is 6561 rs.
To learn more matematics follow the given link
https://brainly.in/question/53081706?
#SPJ2