Question

The cost of a machine is rupees 2,50,000. It depreciates at the rate of 4% per annum. Find the cost of the machine after three years.​

Answer 1

Answer:

rs. 2,21,184.

Step-by-step explanation:

formula for depreciated value =p(1 - r/100)^n

where p is the present cost,

r is depreciation rate,

n is number of years is the time.

so by using the formula we get

=2,50,000(1 - 4/100) ^3

=2,50,000(96/100)^3

=2,50,000*96*96*96/100*100*100

=rs. 2,21,184

so,the coast of the machine after 3 years at depreciation value of 4% is Rs. 2,21,184.

Answer 2

$\bf{\Huge{\boxed{\rm{\blue{ANSWER\::}}}}}$

$\bf{\Large{\underline{\sf{Given\::}}}}$

The cost of a machine is Rs.250000. It depreciates at the rate of 4% per annum.

$\bf{\Large{\underline{\bf{To\:find\::}}}}}$

The cost of the machine after 3 years.

$\bf{\Large{\underline{\sf{\green{Explanation\::}}}}}$

$\bf{We\:have}\begin{cases}\sf{Principal,[P]\:=\:Rs.250000}\\ \sf{Time,[n]\:=\:3\:years}\\ \sf{Rate,[R]\:=\:4\%}\end{cases}}$

Therefore,

$\longmapsto\tt{A\:=\:P(1\:+\:\frac{R}{100} )^{n} }$

$\longmapsto\tt{A\:=\:250000\:(1\:-\cancel{\frac{4}{100}} )^{3} }$

$\longmapsto\tt{A\:=\:250000\:(1-\frac{1}{25} )^{3} }$

$\longmapsto\tt{A\:=\:250000\:(\frac{25-1}{25} )^{3} }$

$\longmapsto\tt{A\:=\:250000*\frac{24}{25} *\frac{24}{25} *\frac{24}{25}}$

$\longmapsto\tt{A\:=\:\cancel{250000}*\frac{24}{\cancel{25}} *\frac{24}{\cancel{25}} *\frac{24}{\cancel{25}}}$

$\longmapsto\tt{A\:=\:Rs.(16*24*24*24)}$

$\longmapsto\tt{\pink{A\:=\:Rs.221184}}$

Thus,

The cost of machine after 3 years is Rs.221184.