the cost of a notebook is Rs. 3a²-4ab+6b². how much would 5a²b²notebooks cost?
please give step by step answer
Answers
Given : -
- The Cost of one notebook is
⠀⠀⠀(3a² -4ab + 6b²)⠀⠀⠀⠀⠀⠀⠀⠀
To Find :- ⠀⠀⠀⠀⠀
- Cost of 5a²b² notebooks⠀⠀⠀⠀⠀⠀⠀⠀⠀
Solution :- ⠀
We know that Formula for finding the cost of 5a²b² notebooks is :-⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀
On putting the values in the formula we get :
⠀
By Disturbing terms we get,
By Taking out the constants,
By applying identity :
By Adding the terms we get,
⠀
Hence, The Cost of 5a²b² notebooks is :
(15a⁴b² - 20a³b³ + 30a²b⁴)
Step-by-step explanation:
Given : -
The Cost of one notebook is
⠀⠀⠀(3a² -4ab + 6b²)⠀⠀⠀⠀⠀⠀⠀⠀
To Find :- ⠀⠀⠀⠀⠀
Cost of 5a²b² notebooks⠀⠀⠀⠀⠀⠀⠀⠀⠀
Solution :- ⠀
We know that Formula for finding the cost of 5a²b² notebooks is :-⠀⠀
⠀⠀⠀\boxed{\sf\red{5a²b² × (cost \: of \: one \: notebook)}}
5a²b²×(costofonenotebook)
⠀⠀⠀⠀⠀
On putting the values in the formula we get :
\sf{⟹5a²b² \times ({3a}^{2} - 4ab + {6b}^{2} ) }⟹5a²b²×(3a
2
−4ab+6b
2
) ⠀
By Disturbing terms we get,
\sf{⟹5a²b² \times {3a}^{2} + 5a²b² \times - 4ab +5a²b² \times {6b}^{2} }⟹5a²b²×3a
2
+5a²b²×−4ab+5a²b²×6b
2
By Taking out the constants,
\sf{⟹(5 \times 3) {a}^{2} {a}^{2} {b}^{2} + (5 \times-4) {a}^{2}a {b}^{2}b + (5 \times 6) {a}^{2} {b}^{2} {b}^{2}}⟹(5×3)a
2
a
2
b
2
+(5×−4)a
2
ab
2
b+(5×6)a
2
b
2
b
2
By applying identity : \sf{{x}^{a} {x}^{b}= {x}^{a + b}}x
a
x
b
=x
a+b
\sf{⟹15{a}^{2 + 2} {b}^{2} - 20{a}^{2 + 1} {b}^{2 + 1} + 30{a}^{2} {b}^{2 + 2} }⟹15a
2+2
b
2
−20a
2+1
b
2+1
+30a
2
b
2+2
By Adding the terms we get,
\sf\pink{⟹15{a}^{4} {b}^{2} - 20{a}^{3} {b}^{3} + 30{a}^{2} {b}^{4} }⟹15a
4
b
2
−20a
3
b
3
+30a
2
b
4
⠀
Hence, The Cost of 5a²b² notebooks is (15a⁴b² - 20a³b³ + 30a²b⁴)