Question

The cost of a plane ticket comist of two parts reservation cost and original price of the ticket. Ramen bought a ticket for mumbai which cost him Rs 10000. Form a linear equation and find atleast three combination of reservation cost and original price.​

Answer 1

Step-by-step explanation:

I find only this☺️☺️☺️☺️☺️

Answer 2

Answer:

$Let \: the \: reservation \: charges \: be \: \\ Rs. \: x \: and \: cost \: of full$

$ticket \: of \: first \: class \: be \: Rs. y.$

$It \: is \: given \: that \: one \: reserved \: first \: \\ class \: ticket \: from \: the \: station \: A \: to \: B \\ costs \: Rs. 2530. \: Also, \: one \: reserved \: first \: \\ class \: ticket \: and \: one \: reserved \: first \: class \: half \: \\ ticket \: from \: A \: to \: B \: costs Rs. 3810, \: therefore,$

$x \: + \: y \: =2530 \: \: \: \: \: \: (1) and$

$since \: plane \: half \: ticket \: costs \: half \: \\ the \: full \: fare, \: but \: the \: reservation \: charges \\ are \: the \: same \: on \: a \: half \\ ticket \: as \: on \: a \: full \: ticket \: so \: we \: get$

$(x + y) + (x + y ) = 3810 \\ \longmapsto{4x + 3y = 7690}$

$Multiplying \: equation \: 1 \: by \: 3 \: we \: get,$

$3x+3y=7590 \: \: \: \: \: \: (3)$

$Now \: subtracting \: equation \: 3 \: from \\ \: equation \: 2, \: we \: get \\ x = 30$

$Now \: substitute \: the \: value \: of \: x \: in \: \\ equation \: 1 \: that \: is: \\ 30 + y = 2530$

$implies \: y=2500$

$\blue{Hence, \: the \: full \: first \: class \: fare} \\ \blue{ from \: station \: A \: to \: B \: is \: Rs. 2500.}$