Math, asked by anjanabarman588, 1 month ago

The cost of a plane ticket comist of two parts reservation cost and original price of the ticket. Ramen bought a ticket for mumbai which cost him Rs 10000. Form a linear equation and find atleast three combination of reservation cost and original price.​

Answers

Answered by KrithikaQueen
0

Step-by-step explanation:

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Answered by mh5767187
0

Answer:

Let  \: the \:  reservation \:  charges \:  be  \:  \\ Rs.  \: x  \: and  \: cost  \: of full

ticket  \: of  \: first  \: class \:  be  \: Rs. y.

It  \: is  \: given  \: that  \: one \:  reserved  \: first  \:  \\ class \:  ticket \:  from  \: the  \: station \:  A  \: to \:  B  \\ costs  \: Rs. 2530.  \: Also,  \: one \:  reserved  \: first  \:  \\ class \:  ticket  \: and  \: one  \: reserved  \: first  \: class \:  half \:  \\  ticket \:  from  \: A \:  to  \: B  \: costs Rs. 3810,  \: therefore,

x \: + \: y \: =2530 \:  \:  \:  \:  \:  \: (1) and

since \:  plane \:  half \:  ticket  \: costs \:  half  \:  \\ the \:  full \:  fare, \:  but  \: the  \: reservation \:  charges  \\ are  \: the  \: same  \: on \:  a  \: half  \\ ticket  \: as  \: on \:  a \:  full  \: ticket \:  so  \: we \:  get

(x + y) + (x + y ) = 3810 \\  \longmapsto{4x + 3y = 7690}

Multiplying \:  equation  \: 1 \:  by \:  3  \: we  \: get,

3x+3y=7590 \:  \:  \:  \:  \:  \: (3)

Now  \: subtracting \:  equation \:  3 \:  from  \\  \: equation  \: 2, \:  we  \: get \\ x = 30

Now \:  substitute  \: the \:  value  \: of  \: x \:  in  \:  \\ equation \:  1 \:  that  \: is: \\ 30 + y = 2530

implies \:  y=2500

 \blue{Hence,  \: the  \: full  \: first \:  class  \: fare} \\  \blue{  from  \: station \:  A \:  to  \: B \:  is  \: Rs. 2500.}

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