The cost of a refrigerator is rs 9000 it's value depreciate at rate of 5 percent every year find the total despreciation in its value at the end of 2 year
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by using compound interest
A=₹9000×(1-5/100)^2
A=₹9000×95/100×95/100
A=₹8122.5 Answer
A=₹9000×(1-5/100)^2
A=₹9000×95/100×95/100
A=₹8122.5 Answer
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