the cost of a second hand car is 125000, a man spend 15000 on its repairs and sold for 161000 . find the profit %
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Answered by
2
cost price = 125000 and repairs cost = 15000
total cost = 125000+ 15000 = 140000
selling price = 161000
profit = (161000-140000)/140000= 21000/140000
= 21/140 now for percentage multiply with 100
(21×100)/140 210/14 = 15%
total cost = 125000+ 15000 = 140000
selling price = 161000
profit = (161000-140000)/140000= 21000/140000
= 21/140 now for percentage multiply with 100
(21×100)/140 210/14 = 15%
Answered by
1
Step-by-step explanation:
Given, u=20m/s
t
1
=5s
t
2
=8s
Graph: (Refer to Image)
(1) Distance travelled in first 5 sec= area of ABDE= 20×s=80m
(2) Distance travelled after the brakes are applied (area of BCD)=
2
1
×8×5=20m
(3) Total distance travelled= AreaofABCDE+AreaofBCD=80+20=100m
(4) Acceleration during the first 5 sec= 0, because uniform velocity.
(5) Acceleration during the last 8 sec= v=0,u=20m/s,t=8sec
⇒v=u+at⇒0=20+a(8)
⇒a=−2.5m/s
2
(slope of the line DC
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