Question

The cost of a slice of banana cake is t cents. The cost of a slice of chocolate cake is (t + 5) cents. The total cost of 7 slices of banana cake and 11 slices of chocolate cake is 2215 cents. Find the value of t.​

Answer 1

☆ Given :-

• Cost of a slice of banana cake = t cents
• Cost of a slice of chocolate cake = t + 5 cents
• Sum of prices of 7 banana cakes and 11 chocolate cakes is 2215 cents

☆ To Find :-

• The value of t

☆ According to the question :-

• 7t + 11 ( t + 5 ) = 2215 cents

☆ Solution :-

$\sf : \implies \: 7t + 11(t + 5) = 2215 \\ \sf : \implies \: 7t + 11t = 2215 - 55 \: \\ \sf : \implies \: 18t = 2160 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \implies \: t = \frac{2160}{18} = 120 \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Therefore, the value of t is $\boxed{ \sf \bigstar \: 120 \: cents}$

Answer 2

Step-by-step explanation:

Given :-

Cost of a slice of banana cake = t cents

Cost of a slice of chocolate cake = t + 5 cents

Sum of prices of 7 banana cakes and 11 chocolate cakes is 2215 cents

☆ To Find :-

The value of t

☆ According to the question :-

7t + 11 ( t + 5 ) = 2215 cents

☆ Solution :-

\begin{gathered} \sf : \implies \: 7t + 11(t + 5) = 2215 \\ \sf : \implies \: 7t + 11t = 2215 - 55 \: \\ \sf : \implies \: 18t = 2160 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \implies \: t = \frac{2160}{18} = 120 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered}

:⟹7t+11(t+5)=2215

:⟹7t+11t=2215−55

:⟹18t=2160

:⟹t=

18

2160

=120

Therefore, the value of t is \boxed{ \sf \bigstar \: 120 \: cents}