Question

The cost of a washing machine is Rs. 6000. Its value depreciates at 6% per
annum. Then, find the value of the machine after 3 years.

Answer 1

Answer:

Cost price of washing machine 3 years ago=Rs. 19440

Depreciation rate per year=16

3

2

%

Price of washing machine after 1 year of purchase =19440−

3×100

50

×19440=19440−3240=Rs. 16200

Price of washing machine after 2 years of purchase =16200−

3×100

50

×16200=16200−2700=Rs. 13500

Price of washing machine after 3 years of purchase =13500−

3×100

50

×13500=13500−2250=Rs. 11250

Hence, present value of washing machine=Rs. 11250

And vaue after 1 year =11250−

3×100

50

×11250=11250−1875=Rs. 9375

Step-by-step explanation:

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Answer 2

Given :

• Cost of the machine (P) = Rs. 6000

• Rate of depreciation (R) = 6 %

• N = 3 years

• A = Depreciated price of the machine

To Find :

• → The value of the machine after 3 years

Solution :

As we know that ,

${\underline{\boxed{ \bf{ \pink{A = P \bigg\{ 1 + \dfrac{R}{100} \bigg\}^{n} }}}}} \bigstar$

$\begin{lgathered}\sf : \implies \:6000 \bigg\{ 1 + \dfrac{(-6)}{100}\bigg\}^{3} \\\\\\: \implies \: 6000 \bigg\{ 1 - \dfrac{6}{100}\bigg\}^{3} \\\\\\\ : \implies \:6000 \bigg\{ \dfrac{100-6}{100}\bigg\}^{3} \\\\\\ : \implies \:6000 \bigg\{ \dfrac{94}{100}\bigg\}^{3} \\\\\\: \implies \: 6000 \bigg\{\dfrac{47\times2}{50\times2}\bigg\}^{3} \\\\\\: \implies \:6000 \bigg\{\dfrac{47}{50}\bigg\}^{3} \\\\\\: \implies \: 6000 \times \dfrac{47}{50} \times \dfrac{47}{50} \times \dfrac{47}{50} \\\end{lgathered} \:$

${ \underline{ \boxed{ \pink{\red{ \frak{ : \implies \: Rs. \; 282000}}}}}}$

∴ The cost of the machine after 3 years will be Rs. 282000