Question

the cost of a washing machine is rupees 10,000 if it cost reduces to rupees 7290 in 3 years then find the rate of depreciation. answer Pata Hai explain kar do ​

Answer 1

Answer:

The rate of depreciation is 10%

Step-by-step explanation:

Let the rate of depreciation is r

cost of washing machine after 1st year

$=10000-10000\times r/100$

$=10000(1-\frac{r}{100})$ Rs.

Cost of washing machine after 2nd year

$=10000(1-\frac{r}{100})-10000(1-\frac{r}{100})\times \frac{r}{100}$

$=10000(1-\frac{r}{100})(1-\frac{r}{100})$

$=10000(1-\frac{r}{100})^2$

In a similar way we can find that the cost of machine after 3 years will be

$=10000(1-\frac{r}{100})^3$

According to the question

$10000(1-\frac{r}{100})^3=7290$

$\implies (1-\frac{r}{100})^3=\frac{729}{1000}$

$\implies (1-\frac{r}{100})^3=(\frac{9}{10})^3$

$\implies 1-\frac{r}{100}=\frac{9}{10}$     (Taking cube root on both the sides)

$\implies \frac{r}{100}=1-\frac{9}{10}$

$\implies \frac{r}{100}=\frac{1}{10}$

$\implies r=\frac{100}{10}=10$

Therefore, the rate of depreciation is 10%

Answer 2

Answer:

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