The cost of an electrical gadget and the cost of a plumbing material were in the ratio 8:6 last year. This year, each cost was reduced by 4.00 and has changed to 7:5 respectively taking the initial cost of the electrical gadget to be P and that of th plumbing material to be q cal the value of p and a
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Answer:
please follow ...........
Given : cost of an electrical gadget and the cost of a plumbing material were in the ratio 8:6 last year. This year, each cost was reduced by 4.00 and has changed to 7:5 respectively
To find : initial cost of the electrical gadget & plumbing material
Solution:
cost of an electrical gadget = 8x = P
cost of a plumbing material = 6x = q
each cost was reduced by 4.00
cost of an electrical gadget = 8x - 4
cost of a plumbing material = 6x - 4
New ratio 7 : 5
=> (8x - 4)/ (6x - 4) = 7/5
=> 5(8x - 4) = 7(6x - 4)
=> 40x - 20 = 42x - 28
=> 2x = 8
=> x = 4
P = 8x = 8 * 4 = 32
q = 6x = 6 * 4 = 28
initial cost of the electrical gadget = 32
initial cost of the plumbing material = 28
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