Math, asked by sumankundu5662, 7 months ago

The cost of an electrical gadget and the cost of a plumbing material were in the ratio 8:6 last year. This year, each cost was reduced by 4.00 and has changed to 7:5 respectively taking the initial cost of the electrical gadget to be P and that of th plumbing material to be q cal the value of p and a

Answers

Answered by akanshakumar76
0

Answer:

please follow ...........

Answered by amitnrw
0

Given :   cost of an electrical gadget and the cost of a plumbing material were in the ratio 8:6 last year. This year, each cost was reduced by 4.00 and has changed to 7:5 respectively  

To find :  initial cost of the electrical gadget  &  plumbing material

Solution:

cost of an electrical gadget  = 8x = P

cost of a plumbing material = 6x   = q

each cost was reduced by 4.00

cost of an electrical gadget  = 8x - 4

cost of a plumbing material = 6x  - 4

New ratio  7 : 5

=> (8x - 4)/ (6x - 4)  = 7/5

=> 5(8x - 4) = 7(6x - 4)

=> 40x - 20 = 42x - 28

=> 2x = 8

=>  x = 4

P = 8x  = 8 * 4 = 32

q = 6x = 6 * 4  = 28

initial cost of the electrical gadget = 32

initial cost of the  plumbing material = 28

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