Question

The cost of an electronic device reduces at the rate of 5% per annum. If its present cost is 32,490 Rupees what was the cost before two years.​

Answer 1

Answer:

present value = Rs 411540

rate of depreciation = 5% p.a

present value = Rs 411540

rate of depreciation = 5% p.a

t = 3 years

value 3 yrs ago= p(1 – 100)"

⇒ 411540 = p(1 – 100)³

⇒ 411540p(15) ³

⇒ 411540p(10) ³

⇒ 411540p(6859) 3 8000

411540x80000

6859

Rs480000

t = 3 years

value 3 yrs ago= p(1 – 100)"

⇒ 411540 = p(1 – 100)³

⇒ 411540p(15) ³

⇒ 411540p(10) ³

⇒ 411540p(6859) 3 8000

411540x80000

6859

Rs480000

Step-by-step explanation:

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Answer 2

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A] present value = Rs 32,490

rate of depreciation = 5% p.a

t = 2 years

value 2 yrs  ago=p(1−100R)n

⇒32,490=p(1−1005)2

⇒32,490=p(10095)2

⇒32,490=p(2019)2

⇒32,490=p(80006859)2

⇒6859411540×80000=Rs480000